Smooth solution for 2nd euler problem
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euler2.c
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15
euler2.c
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#include <stdio.h>
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int main( int argc, char *argv[] ) {
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int fib_even=2,fib_prev=1,fib_tmp;
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int sum=0;
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while(fib_even < 4e6) {
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sum += fib_even;
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fib_tmp = fib_prev + fib_even;
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fib_prev = fib_even + fib_tmp;
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fib_even = fib_prev + fib_tmp;
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}
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printf("%d\n",sum);
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return 0;
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}
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